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CAMBRIDGE INTERNATIONAL IGCSE™ PHYSICS 0625 · EXAMINATIONS 2026–2028 · CHAPTER 1 · LESSON 4 · CORE + SUPPLEMENT / EXTENDED

Acceleration and speed-time graphs

This is Cambridge International IGCSE Physics 0625, separate from the Egyptian Baccalaureate / Thanaweya Amma and not a Year 3 course. Last lesson you read motion graphs. Now you will use their areas to find distance. The book marks acceleration calculations and graph gradients as Supplement / Extended only, so those parts are clearly labelled.

LEARN · STEP 1 OF 6 · CORE

A speed-time graph can tell you distance

Time runs along the bottom; speed is read up the side. For a short time interval, distance = speed × time. On this graph that multiplication is the area between the line and the time axis. So the area under a speed-time graph represents the distance travelled.

Open the worked example

A toy car travels at 6 m/s for 10 s. The graph makes a rectangle: width = 10 s and height = 6 m/s. Area = 10 × 6 = 60 m. The units work too: seconds × metres per second = metres.

Quick check: A runner moves at 4 m/s for 8 s. What is the area under the flat graph line, and what does it mean?

Think, then reveal: Area = 4 × 8 = 32 m. The area means the runner travelled 32 m.

INTERACTIVE ACTIVITIES

See what the graph’s area and gradient mean

Explore the area under a speed-time graph

Choose a journey. Before opening the working, predict the distance from the shape underneath the line.

time / sspeed / m/sA whole train journeyshaded area = distance
Add each shape’s area to find total distance. A descending line means slowing down, not moving backwards.

Total distance = 900 m

Reveal the area calculations
  • First triangle: ½ × 10 s × 20 m/s = 100 m
  • Rectangle: 30 s × 20 m/s = 600 m
  • Last triangle: ½ × 20 s × 20 m/s = 200 m

Add them: 100 + 600 + 200 = 900 m.

Explore acceleration (Supplement / Extended only)

Adjust the starting speed, final speed and time. Notice that braking makes final speed smaller, so the calculated acceleration is negative.

a = (v − u) ÷ t = (17 − 5) ÷ 4 = 3.00 m/s²

time / sspeed
The straight line has one constant gradient, so acceleration is constant.
CHECK YOUR LEARNING · 11 ORIGINAL QUESTIONS · CORE + SUPPLEMENT / EXTENDED

Practise, then read the explanation

Questions marked Supplement / Extended use the extra acceleration ideas. Try the question first, open the optional hint if you need help, then submit for the worked reasoning.

Answered 0 / 11 · Correct 0

Question 1 · Area at constant speed · Core · 3 marks

Optional hint

For a horizontal speed-time line, the area is a rectangle: base × height.

A tram travels at a constant 12 m/s for 25 s. What distance does the rectangle under its speed-time graph represent?

This original interactive lesson and practice set align to Cambridge IGCSE Physics 0625 syllabus links 1.2.4, 1.2.5, 1.2.7 and 1.2.9–1.2.12 as identified in Volume A, Lesson 4. Core speed-time graph interpretation and area questions are separated from Supplement / Extended acceleration calculations, gradients, negative acceleration and changing-acceleration graphs. Source reading: Physics-0625 Volume A, PDF pp. 27–32 (printed pp. 19–24).

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